Question

a. The pH of a strong base solution is eaqsy to calculate because the salt molecule dissociates 100%. So if 2.5 moles of NaOH are dissolved in water, that solution will have how many moles of OH^- ions?

b. If 0.03 moles of Ca(OH)₂ are dissolved in water, that solution will have many moles of OH^- ions?

Answer 1

As dissociation of NaOH (strong base is 100%), then all of the moles of Naon are converted into Nat and on Further depending upon stoichiometry of ren , we get no. of moles of products. nat ton Molls Initially Naon 2.5 Finally 2.5 2.5 No. of moles of ol - Stochiometry of on in run X no. of moles of NaOH - 1x 2-5 = 2.5 moles so (OH) ions = 2.5 moles 2 For CaOH (stong base ) : dissociates 1001 cakt + 204 Moles initial - Moles final Ca(OH)2 0.03 - 0.03 2X0-03 No. of moles of on. Stochiometry of (oh) in runx no- of moles of Ca(OH)2 - 2 x 0-03 = 0.06 moles so moles of on ions { stoichiometry cofficient in balanced chemical rsen?