Question

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ME General Chemistry I Molarity of Acetic Acid in Vinegar: A Titration Experiment NaOH = 40.019/mols NaOH DATA AND CALCULATIONS STANDARDIZATION OF NaOH lesina Check the 2 (at least) trials O O O Check the 2 (at least) trials used to calculate the average molarity. Trial 1 Trial 2 Trial 3 Mass of KHP Moles of KHP 1991/ 37.50 m2 read - 1-0.72893 0 7599 0.75792- 16,59 Initial buret reading 7.13-0.30ml 15-Semb 31.5em 115.594 Final buret reading 15.59 m2 37.50ml 42 49 37. ead Volume of NaOH used (5.29mL 16.99 ML 15.91 m2 Moles of NaOH used 0.018 2 0.0190 0.0189 Molarity of NaOH 1.19M 1191 1.19 M Average molarity of NaOH 1.19 M

Answer 1

Koco a KHP = Potassium hybrogen phthalate Molecular weight Of KHP LOV =411288) +(1684) +(145)+39] z Ou Hg K = 204 Reaction with Nooth Nao ok. Noocook NOOH + Holok So ) oro + H2O 50 1 mole KHP reacts with 1 mole as NooH. So, moles of KHP reacted = moles of Nach reacted Trial-2 i Trial-1 L 0.72893 g Terial-3 Mass of KHP 0.7599 g 0.75792 g moles of KHP 10-72893) 204 110 7599 204) (6 757921 -0.00357 206 = 0.003 74 = 0.00372 Inial buut Reading 0-30 me 315.ome 15:59 me Final burat 15.5g me 47.49 me 3150 me Reading 15- 28 me 15.99 mel 15.91 me Volume of NaoH used

Terial-1 Terial-2 Tersal-3 moles of Nach used (same as moles of KHP) 0.00357 0.00372 0.00371 Molarity of NaOH 0-00357 x 1000 0.0037241000 0.00371x108 15.29 15.99 moles of NaoH x1000) 15-91 volume of NooH = 0.224 M = 0.232M 10.233m so, Average molarity of Nach (0.224 +0-232 to 233 - 0.23 M

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