Question

4. Given the d orbital splitting diagrams below, determine which M and calculate the CFSE for each. EXAMPLE PROVIDED The metal has THREE d electrons; H2O is neutral and Br is a -1. The overall chage on the metal complex is +1 LLL M + -1 = +1 M +2 charge M that has lost 2 electrons and has 3 electrons left therefore M = V (which has 5 valence electrons as a neutral metal) M(H20)Br* CFSE - 3(-2/5)Ao 6/5 Ao III l I 1 1 1 1 1 1 dxy dyz dx M(CN)62 M(H20)62- MCI

Answer 1

1 1 1 1 day dag dyz M(H2O 2 + +2. The metas otras 4 d elections , The H₂O is a neutral ligand. And the overall charge of the complex So, the charge on the metal is , - +14 Mto=+2 = =+2 That means the metal M lost a elections and has 4 electrons left. So, the no. of nalence elections of the metal is b. So, the metal is C with electronic configuration e [au]43'3 do G²+ : A4)3 d So, i la And CF SE = (3 (-0.4) + 0.6.) A. = -0.6 40 . . ..7 ca and cf's & 2-0.6 to (Aus.) s hor M(H20)6 So, for M(H₂o) 27, Mis ?

1 1 1 1 day dag dygs на 4- The metal has 6 d élections, notar ut The charge of ce is n o t est And charge of overall complex in 4. Son So, the charge on the metal, is aut e M+6(-1) = -4 =) M-6=-4 =) M 2 6-4 T So, charge on metal is to do That means, the metal lost a elections and har 6 electerons left. So, the no. of valance electr of the metal M is s. so the metal is fe and the electronic conoleguration is er Ar] 4 5 3 do rezt: [Am] 3 db and So, mire And CA SE = (4 * (-0.4 + 2x0.67A. (106 +12) 4. -- 0.4 to Hence, for melho Mis fe and efst is -014 Ao (Aus)

IL 12 in 1 day daz dyz M(CN) The metal has 6 de electrons. The charge of cN is at And overall charge of the complex is -2 So, charge on the metal is, M + 6(-1) = -2 =) M-6=-2 M = 6-2 24 So, charge on metal is + 4 .. That means, the metal or lost 4 electrons and has 6 elections left, so the no, of valence elections of M is 10. So, the metals Ni with electronic configuration, Ni: [Am] 45² 3d8 Neht : [Ah] 3 do So, M z Ni And case = 6X(-0.4) Ao = -24 40 Hence, for M(CN) Min Ni and ease is 2.40 (Aus).