Question

In a mixture of gases, how is the total pressure determined? How is the partial pressure of a gas in a mixture calculated? Determine the total pressure of a gas mixture that contains oxygen, nitrogen, and helium. The partial pressures are: Pax =20.0 kPa, Pz = 46.7 kPa, and P.. = 26.7 kPa. A gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure of 32.9 kPa. If Po6.6 kPa and P2 = 23.0 kPa, what is Poz? A person using an oxygen mask is breathing air with 33% O. What is the partial pressure of the O, when the air pressure in the mask is 110 kPa? A sample of nitrogen gas is collected over water at a temperature of 23.0°C. What is the pressure of the nitrogen gas if atmospheric pressure is 785 mm Hg? The vapor pressure of water is 21.1 mm Hg. Hydrogen is collected over water at 0.975 atm and 28°C: What is the partial pressure of H? PHOS 0.037 am CO2 gas is collected over water at 100.3 kPa and 19°C. Find the pressure of the dry gas. PHO= 2.19 kPa

Answer 1

17 calculation a total pressure- - from Dalton's partial pressuce law, at const. temp, the total pressure q an non-realting gates is equal to the Sum of the individual partial messules qa gaseous monture. a Ptotal = Pit P2 + P3+---+Pm 2) Calculatim q partial pressure q am gas in a mixture The partial pressure of an ondividual gas in an gaseous mixture is given by 'Pi' & it is equal to product of total pressure q gascous moiture and mole fraction of that individual gas. pi= Ptotal **;) individual gas xi= mode fraction of

; 3) Given that Po= 20.0 kPa PN₂ = 46.7 kPa PH2 = 26.7 kPa Here we have to find total pressure q mont .. Plotal = Port PN2 + PH2 noontule = 20 kipa t 46.7 kpat 26.7 kpa Ptotal = 93.4kpa. Total pressue q. the gaseous moittau= 93.4kpa. 4. Given that Ptotal = 32.9k pa Po2 = 6.6kpa Pra= 23.okpa PcO2= ? - Ptotal = POR + PN2 + PEOR = 32.9kpa= 6.6kpa+23.okpa + PCO2 =) PCO2 = 32.9Kp - 29.6 kpa - PCO₂ = 3.3kpa ... paitical pressure q RO2 (PCO2) is 3.3kpa. 5). Given that Ptotal= Pair = llokpa mole fraction of O₂ = 20 = 33% = 33 120₂ = 0.33 a. partial pressure of O2 = Por=202* Ptotal =) PO2 = 0.33 X 1lokpa = 36-3k pa . paltial pressure of O₂ = P02= 36.3 kpa. 100

16. Given that atamospheric pressure 2785 mm Hg. rapour pressure a water aal.4 mm Hg Here we have to find, pressure of Ne gas. He know that, atmosphen2 presuce - Vapour presswica water + pressure of Nz gas = f 785 mm Hg = 21.1 mm Hg + PN2 = PN2 = (785-21.8) mm Hg = 763.9 mm Hg 2. pressure q Nz gai PN₂ = 763-9mm Hg 7. Given that Patm = 0.975 atm. PH2O= 0.037 am ... PH2 = ? - Patm = Phao + PH2 =) PH₂ = Patm - Phao - 0.975 atm - 6.037 atm - PH2 = 0.938 atm A partial pressure of H2 PH2 = 0.938 atm. 8. Given that Patm = Ptotal = 100.3 kpa & PH2O=2.19k pa . Patm = PH₂O + Pdey gas » Paey gas = 100.3 kpa - 2.19 kpa Peor = 98-11kpa .: partial pressure of dez gas = 98.11 KB a gas = 98.11 kpa
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