Question

Suppose 1.59g of sodium bromide is dissolved in 150. mL of a 39.0mM aqueous solution of silver nitrate.

Calculate the final molarity of bromide anion in the solution. You can assume the volume of the solution doesn't change when the sodium bromide is dissolved in it. Be sure your answer has the correct number of significant digits (M)

Answer 1

39 mm or 39x100 m AgNO3 solution means - contains 39x103 mole AgNO3 1000 ml solution a. 150 mln " (398103 x 150) mole AgNO3 = 5.85X103 mole AgNO3 . No. of moles = – given mass molar mass morar mass of Nabr (sodium bromide) = 102.9 g/mole i to 59 g 1.59 g Nabra. 102.9 og (mole Nator - 1.545x102 mole Nabr