Question 7 1 pts Calculate the work done on the system when 2.0 mol of an...

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science chemistry

Answer 1

Answer #1

Answer -6900J

We have work done= -PdV

Also we have PV= NRT

Therefore P= NRT/V

Therefore Work done = -NRT ln (V2/V1)

here N=2 mole

T=298k

R=8.314 J/K-mol

Putting down the values we have

Work done = -2*8.314*298*ln((0.5/2))

=6900J

Answer 2

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