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Data and Calculations Trial 0:29 Absorbance 0.378 Je 0.086 Trial 2 0.47 Trial 3 0.632 Trial 4 0.729 0.686 Absorbance of stand
CHEM 1412 - Expt 5: Determining ko Processing the Data 1. Write the Ke expression for the reaction in the Data and Calculatio
ke CHEM 1412 - Expt 5: Determining Kc 5. Determine the [Fe3+]e for each trial: To find the Fe concentration at equilibrium ([
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(SN). KG(N 0002 1*2X103 totalmi = 0.6002 m value of table-4 Fe(NO 32 Absorbanceso & Fe(NO 3 st Absorbamstd D o. 126 xo co osm4) 40:8/10 20:408. 5) 22:3/100 = 0.223 Evet A = -log(5) A cloå748) = 0.126 A = -log (6.597 - 0224 A =-10 g 60:480) = 0.3.18 AA- -log(TD in DA - - log (0.859) = 23 A -- log (0.422) = a - 109 (0.245 2 A log (0.143) = 5 A - log (6 9.9) 0.066 0.374 0.610* Answer & datu Table - 2 Initial No life (NO₂) 0.05M 0.osm 0.05m 0.05m 0.05m final [KS CN] [Fe(NO2) 0.00006 0.00005 0.0ool 0

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