Calculation of percent yield of [Co(NH3)5Cl]Cl2: I'm having trouble with these steps: Calculation of limiting reagent...

Question

Question

Calculation of percent yield of [Co(NH₃)₅Cl]Cl₂:

I'm having trouble with these steps:

Calculation of limiting reagent for synthesis of [Co(NH₃)₅Cl]Cl₂ (assume H₂O₂ present in excess)
Calculation of theoretical yield of [Co(NH₃)₅Cl]Cl₂

These are the reactants we used: 2.010g NH₄Cl, 15mL 15M NH₃, 4.067g CoCl₂6H₂O, 3.2mL 32% H₂O_2, 15mL 12M HCl

This is the equation used: 2CoCl2*6H2O + H2O2 + 8NH3 + 2NH4Cl --> 2[Co(NH3)5Cl]Cl2 + 14H2O

science chemistry

Answer 1

Answer #1

2 loc.6 Hotho + 8 NH₃ + 2NH₂4 0.225 0. 225 0.037 0.03 tlumo 0.02 2 [LO (NY) U] 4₂ (LR) NHAU = 2.019 = 2 2 20.03757 mole. MN3

Simply using mole concept we can get answer..

Answer 2

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