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A chemist prepares a solution of sodium nitrate (NaNO,) by measuring out 542 mol of sodium nitrate into a 100 ml. volumetric
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Answer) moles of NaNO₃ (n) = 54.2 umol = 54.2x10-3 mmol volume of solution (N) - 100 ml = 0.16 Molarity = n 54.2x10-3(mmol) 0

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