Question

Calculate pressure using Dalton's law of partial pressures. A gas mixture is made up of Xe (40.1 g), He (1.29 g), and Kr (26.9 g). The mixture has a volume of 26.4 L at 32 °C. Calculate the partial pressure of each gas in the mixture and the total pressure of the gas mixture. Pxe = PHe = Pkr = Ptotal = atm atm atm atm

Answer 1

I lot of 4 we let to know that is pontial pressure Partial pressure : I In a mixture of non-reacting gases, partial pressure of any component gas is defined as pressure enterted by the individual gas if whole of the minture had been occupied by this component only. for three gases A, Bloguses are not reacting, are mixed having number of moles nA , NB & me :- - pasitial pressure of A, refpA = XARP Jo

& Partial poressure of B is TB = XB * Prored. 1 - • Partial pressure of c is le = xe Protel - (3) e whore XA, XB & Xe care mole traction of A, B do greses, & IX = na L Nathatna XB & NB HAT not no hatnothe e Here NA IRB and me are moles of A Blace gases total pressure of gaseous V Total & mintare.

• Since hose gases are xe, He & kr in place of A B and Hence wil will use formula in terms gases given. Now according DALTON'S LAW 7 At given temperature, the total pressure of excorted by two or more non reacting gases occupying definita volume is equal to sum of partial pressures of component gases. Protal = x + Pret Pro o pxe, Pre & pkr are postial pressures of xo, Hes STEP calculation of number of moles. (9 xe cuorg) for xe Atomic wt = 13113 qm.

Number of moles - mass ingram Atomic mass or grom. atomic mass & moles of xe = mass of xe Atomic wt of xe = 0.305 nxe & uol Bl. 3 Inxe = 0.31 - (b) moles of He: - Moles - 1-29 .0032 mass of He Atomic weight of He u 3 - In the = 0.32 (②) moles of Kr ! 26.9 -0.32 moles - mass of Kr - Atomic weight ? 83.798

- Imoles of Kr = 0.32 nkr=0.32 STEP 8 EP 8 calce calculation of mole fractions : E for xe mole fraction of xe v noe nxet Het nur -) Xxo = 0.31 0.31 0.gs 0.326 0.31+0 1327 0.32 . ~ Foo He Mole fraction of He 'He a ne nxe thret nko He = 0.32 0.336 0.95 -

Mole fraction of kr nur 0.32 0.95 nxet Hethur X = 0.336 = 0.34 * = XRT=0.34 - ☺ - STEP Calculation of totaal pressure it . Temperature T = 32° = 305kolvir. Total Pressure & (naeth Het hkr). : - Total presser CRM & Cou3lt oog 2 40.325x 0108214 305 2 2614 1 x 0.0821 X 305 26:4 = 0.95* o.gy Ongolo Total pressure & Orgolo = atm Answer

STEP Calculation of partial pressure to Can for xe Mole fraction Total pressure (PTotal) i oogolo at of xe = 1 x = 0.33 | A PARTIAL PRESSURA - MOLF FRACTION X TOTAL PRESSURE Pxe = 0.33 Xoo golo = 0.297 el pressure of xe = 0.297 E b For Me Partial pressure = x Hex Protel Pue 0.3ux oigolo [ partial pressure of He 0.3061

(eg for kr partial pressure of Ko pkg = Xurx P Total - pkg = 0.34 x 0. golo = [BR = 0.306 CONCLUSION : Pxe = Pue = PR = 0.297 atm 0.306 atom 0. 306 atm Protel & Ongolo atm