Question

Data Standard solution: NaOH concentration 0.25 M Volume of HCl used (Va) Initial NaOH buret reading Final NaOH buret reading Volume of NaOH used (Vb) Concentration of HCl (Ma) 10.00 ml 2.00 ml 16.10 ml 14.10 ml Determine the Molarity (concentration) of HCI using the data you collected and the titration formula. (The concentration of the NaOH used was 0.25M) Record your answer on your data form. United States Focus

Answer 1

a) NadH concentration (30) = 0,25 (M) valume of NaOH used (Vo) = 14:10 und volume of Hell cused (Va) – 10.00 und d enor Hal concentratida (sa) we don't know, to determine sa we lose The Roomeda ne Vaxba = Vy x bs. so - V6 x 36 14.100.25 CM) 10

- Sa = 0.3525 (M) Odl, concentration of Hal = 0.3525 (M) TA) 75 ml of a D.5 (M) Hel solution to neutralize 55 und of a bause of unknown concentration u. valume of Hell (a) = 75 and concentration of Had (SA) = 2.5(M) volume of Base (Vg) = 55 and. Concentration of Base (32) = ? - MX3, = V2X512 boabe - 75*0.5 ~ 3.489m) V 55 -3.41 A concentration of unknown basic solution 3.42 (M) = 3141(M) 187 Actual concentration of the Hed was 0+33 (M) when you calculate percent error you have to know Actual value & expellimental value. At, Initially we calculate the concentration of Hel = 0.3525(M) - This uns from experimental value. percentage error exporession,

7 error experimental value-Actual valuel, 100 Actual value (0:3525 - 0,33) MIDO 0.33 OrO225 X 100 0.33 - 6.818 & V. everam 6618181 10) as volume of dake water staken (V) = 1000 mL volume of Base taken (V2) = 0.100 mL concentration of Base (32) = 0.100 M we wants to know the concentration Oh, malarity of the acud in the lake water ab, To determine bi we use the formuda, 1997 W, X5, = V2 x 32. 1 s. - Vzxb2 0.100x 0.100 0.0 1000 1000 (M) 3. = 1x10-5 cong = 1005 cm) mg unatcha lake water, 31 = 10 A malarity of the Acid

1076) Haid concentration, b1 = 10 mg & BH meand potential of Itt I non. So, BH - mathematical form, pH = -log [+] =-Jog [105 ] [:by=cone of Acid] = 10-5 (my I pH = 45 A pH of the lake water = 45