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Suppose 8.00 g of CH4 is allowed to burn in the presence of 15.30 g of oxygen. CH(g) +202(g) +CO2(g) + 2H2O(9) - Part A How mHow much (in grams) CO2 remains after the reaction is complete? 10.5 g Submit Previous Answers ✓ Correct Correct answer is sh

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Mole of Chu= weight - Molar mass 4 = 0.5 mole mole of oxygen = weight of 02 1503 molan mass of o2 32 = 0.u78 mole CHu + 202 C

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