Consider the reaction, 4Fe+3O2-->2Fe2O3.
could you correctly represent 3 molecules of oxygen as (O2)3?
Explain your answer.
No ,we can't use (O2)3 . because the stable state of O2. So to represents 3 molecules of O2 , we should use 3 O2.
Consider the reaction, 4Fe+3O2-->2Fe2O3. could you correctly represent 3 molecules of oxygen as (O2)3? Explain your...
Iron reacts with oxygen at high temperatures to form iron(III) oxide. 4Fe(s)+3O2(g)⟶2Fe2O3(s) Suppose 14.2 g of iron (Fe) is reacted with 18.1 g of oxygen (O2). Select the limiting reagent. Fe2O3 O2O2 FeFe Calculate the theoretical yield of iron(III) oxide (Fe2O3Fe2O3). theoretical yield = The reaction produces 5.40 g of Fe2O3. What is the percent yield of the reaction? percent yield =
Separate the redox reaction into its component half‑reactions. 3O2+4Fe⟶2Fe2O3 Can you please include step by step explanation?
Consider the reaction: 4Fe(s) + 3O2(g) à2Fe2O3(s) DHo= -1652 kJHow much heat is involved in the process if 25.6 g of Fe(s) reacts with 13.5 g of O2(g)
In the laboratory, you react 15.2 g of Fe with O2 according to the balanced chemical equation below. This reaction produces 18.6 g of Fe2O3. What is the percent yield of Fe2O3 for this reaction? Round your answer to the nearest whole number percentage (i.e. 77% instead of 76.7%) 4Fe + 3O2 → 2Fe2O3
The chemical reaction that causes iron to corrode in air is given by 4Fe(s)+3O2(g)→2Fe2O3(s) 4 F e ( s ) + 3 O 2 ( g ) → 2 F e 2 O 3 ( s ) and ΔrH∘ Δ r H ∘ = −1684 kJ mol−1 = − 1684 k J m o l − 1 ΔrS∘ Δ r S ∘ = −543.7 J K−1 mol−1 = − 543.7 J K − 1 m o l − 1 part...
Yellow-green spheres represent fluorine atoms and red spheres represent oxygen atoms, and all the molecules are gases. Reactants Actual products Part A Write a balanced equation for the reaction. Express your answer as a chemical equation. Identify all of the phases in your answer. = AE O 2 ? Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B Identify the limiting reactant. Express your answer as a chemical formula. AD A 2 ? Part C...
Consider the reaction of methane with ammonia and oxygen. 2CH4 (g) + 2NH3 (g) + 3O2 (g) -> 2HCN (g) + 6H2O (l) Determine the limiting reactant in a mixture containing 136 g of CH4, 231 g of NH3, and 501 g of O2. Calculate the maximum mass (in grams) of hydrogen cyanide, HCN, that can be produced in the reaction. The limiting reactant is: 1. O2 2. CH4 3. NH3 Amount of HCN formed = g
Consider the reaction for the combustion of methanol (CH3OH): 2CH3OH+3O2⟶2CO2+4H2O What is the mass of oxygen (O2) that is required to produce 579g of carbon dioxide (CO2)?
Elemental S reacts with O2 to form SO3 according to the reaction 2S+3O2→2SO3 as depicted here.(Figure 1) (Part A) How many O2 molecules are needed to react with 4.41 g of S? (Part B) What is the theoretical yield of SO3 produced by 4.41 g of S? (Part C) For each of the given situations, indicate whether S or O2 is the limiting reactant. 1. 3 mol sulfur, 5 mol oxygen 2. 3 mol sulfur, 4 mol oxygen 3. 3...
Oxygen gas reacts with powdered aluminum according to the reaction: 4Al(s)+3O2(g)→2Al2O3(s) What volume of O2 gas (in L), measured at 774 Torr and 29 ∘C , completely reacts with 52.0 g of Al? (answer in Litres)