Titration is a quantitative analytical volumetric technique that permits the determination of the unknown concentration of an analyte with a known concentration titrant. This is possible because the two react in a known stoichiometric manner allowing calculation of the unknown concentration.
Here the titration is between a standard solution against Ascorbic acid
The over titration of Ascorbic acid even after the end point will make wrong the calculation of the concentration of the unknown solution.
Accuracy refers to the closeness of measurement to the specific value. Over titration leads to a large difference in actual value to the measured value. Its accuracy is lost
After completing the end point the colour of the solution become brighter and brighter and the same end point may not be possible to speculate each time. So each time the end point of the student will be different. So the precision of the titration will be also wrong i.e., the student is not going to get the same value of concentration or volume at each step. Precision is the closeness of measurements to each other.
With regard to the concentration of ascorbic acid, it will be low from the calculation.
question 1-3 Page 4 of 4 Part B: Determination of Ascorbic Acid Trial 1 Trial 2...
EXPERIMENT 25 REPORT SHEET Determination of the Dissociation Constant of a Weak Acid Trial 3 B. Standardization of Sodium Hydroxide (NaOH) Solution Trial 1 Trial 2 Mass of bottle + KHP Mass of bottle Mass of KHP used 0.503 0.545 Final buret reading Initial buret reading mL of NaOH used 26.90mL 1.OOML 20.40m 100mL Molarity of NaOH Average molarity (show calculations and standard deviation) Standard deviation (see Experiment 8) Trial 3 B. Standardization of Sodium Hydroxide (NaOH) Solution Trial 1...
B. Determination of the Molarity of Unknown Acid Trial 1 Trial 2 Trial 3 Mass of Erlenmeyer flask (g) 124 g Mass of Erlenmeyer flask+acid After adding 5 mL HCl solution (g) 135 g Mass of HCl solution (g) Mass of HCl solution (kg) -------- ------ -- Volume (acid), mL ----5mL------- -----5 mL--- ------5mL---- NaOH Initial Volume (Vi) 0.00 mL ------------mL -------------mL NaOH final Volume (VA) 16.5 mL ----------- -------------m L ml ---------mL NaOH Volume Used Vi-Vi --------mL L
Experiment 10 An Acid-Base Neutralization Reaction A. Determination of Unknown Acid Concentration Trial Trial 2 Trial 3 Trial 4 Volume of acid 10m 10m 10m 10mL Final buret reading- NaOH (mL) To.8ML 23.8ml 26.2m4 29.4m Initial buret reading- NaOH (mL) Volume of NaOH required to reach the end point. V 10.8m. 13ML 2.4mL 3.2mL Molarity of the acid, M. 10. OmL/108m./23.8mL 26.2mL) Unknown acid number: 16 Molarity of NaOH: Average Molarity of acid 0-1076m Show all calculations for trials 1...
in the part 2- Determination or percent acetic acid in
commercial vinegar. Mass of vinegar= 4.026g,initial volume of NaOH
=0, final volume of NaHO =41.2,volume of NaOH used=41.2.what's the
Moles of base,Moles of acid , %Acetic acid,and the Average%?
Part 1 - Standardization of NaOH solution Triall Trial 2 Trial 3 1. Mass of PAT ossig o.sogg: 0.5538 2. Initial volume of NaOH 3. Final volume of NaOH 37.3mL 32.0L 3.5 4. Volume of NaOH used (#3 - #2) 37.3m2...
0 Mava=mV6 XvP Soma = Moub - Vaan. Determination of the castante Weak Acid D. Concentration of Unknown Acid Trial 3 - Trial Trial Volume of unknown acid Average molarity of NaOH from above mL of NaOH at equivalence point Molarity of unknown acid Average molarity (show calculations) Standard deviation QUESTIONS 1. What are the largest sources of error in this experiment? 2. What is the pH of the solution obtained by mixing 30.00 mL of 0.250 M HCl and...
Observations: Part 1-Standardization of NaOH Ceho Trial 1 Trial 2 Trial 4 Trial 3 Initial mass weighing vial plus KHP と139 16908 427 IS 4 Final mass weighing vial plus KHP is.118 1s.YT 4.47 Mass of KHP Co 498 Moles of KHP used Moles NaOH used 0.00245% 10.00240円 10.00245 (4 SF) 062453 Initial burette reading of NaOH solution to +/-0.01 mL 00 100 0-00 T10 Final burctte rcading of NaOH solution 19.10 1f 03 02 23.00 to +-0.01 mL. Volume...
U Experiment 17B: Acid-Base Titration Report Data Table Trial 1 Trial 2 T Trial 3 Volume of Acetic Acid Final buret reading 42.35 27.67 Initial buret reading 30.00 38.32 5.81 32.51 30.00 44.40 3.95 40.45 Volume of NaOH 27.67 Exact Molarity of NaOH (From 17A or see label) 1252 Calculations: 1. Calculate the molarity of the acetic acid for each trial and the average molarity Trial 1: Trial 2: Trial 3: Average Molarity of Acetic Acid = 2. Use the...
Determination of the Molarity of a Sodium Hydroxide Solution Trial 1 Trial 2 Trial 3 Weight of KHP: 0.705g 0.702g 0.705g Starting Buret Reading: 4.00 mL 4.00 mL 4.00 mL Ending Buret Reading: 39.20 mL 36.70 mL 37.50 mL mL of Titrant Used: 35.2 mL 32.7 mL 33.5 mL mmole of KHP: mmole of NaOH: Molarity of NaOH solution: Average Molarity: Fill in the table and show work please.
Can someone help me with part B. using the information of part
A. Pleaseeee help as soon as possible.
A. Standardization of Sodium Hydroxide (NaOH) Solution TH 2 155 3.5558 3.55 6.055 0.053 Trial 3 3.5628 3.55 0.0623 2157 ml 1670 ml 2.81 ml 18.70 mL 16.10 ML 2.60 ml. TARI 1 Mass of bottle +KHP 3.5538 Mass of bottle Mass of KHP used Final buet reading 16.10 mL Initial buret reading 13.61 ml ml of NaOH used 2.49 mi...
ratra 1z 1 t B: Detes Name Date inoe Acid-Base Titration Data and Calculations Part A: Standardization of NaOH solution, Data: Trial 1 Trial 3 Trial 2 Initial level, HCI buret 26-60 mL Final level, HCI buret 33.85 mL 43.15 2u.95 mL mL Initial level, NaOH buret 00mL Final level, NaoH buret 23.45 mL 44.35 mL 24.25 mL Calculations: Trial 1 Trial 2 Trial 3 Total volume HCI solution 24.45 mL 33-86 mL 43.95 mL 0.1030 Molarity of standardized HCI...