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s. When one adds a 0.10 M NaOH solution to a weak acid solution, a portion of the weak acid solution is neutralized. If 20.8
Remembering that indicates molarity, lets have a closer look at the ratio [A]/[HA], which put in words is the ratio of neutr

please show all work! The second pic is the formula i think you use but i am confused. Thanks!
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Quesion: when one adds a 0.10 M NaOH solution to a weak acid solution, a portion of the weak acid solution is neutralized. If 20.8 mLs of a 0.10 M solution of NaOH is needed to completely (100%) neutralize 10 mLs of a weak acid solution, how many mLs of the 0.10 M NaOH solution is needed to neutralize 50% of the weak acid solution? To neutralize 30% of the weak acid solution?

M Sol: Gtiven Volume of Nach for 100 % noutaaliyotion (VI) € 20.8 mts. Strength of NGOH (Nm) = 010M Volume of weak acid (Ve)@ For 50% hortialization of weak acid, the required amount of Nach = 50 x 20.8 mts. 100 € 10. A mis. V,N2 The percentage of n

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