Question

4.00 g Na2CO3 is dissolved in H2O and titrated with HCl. 48.0 mL of a HCl solution were required to titrate the Na2CO3 solution. What is molarity of HCl solution?

Na2CO3(aq) + 2HCl(aq) --> 2NaCl(aq) + H2O(l) + CO2(g)

Answer 1

Na.uzaq) + 2HCl aq) anal (aq) + H20) + Co. 6 titration. given 4oog of Na₂CO3 dissolved in H₂O 48.0mL of rice solution used in M.w.op 7 Now, in 4.00g of Na, wz, mole of Na, w = 4.0 g 13 To6g/mol L Na2CO3 = 1068/md mole of nazo = 3.78x10?mole. from stiochiometric of reaction we can see I mole of Na, 63(aq) required = mole of HCl 503-78 X10-?mole ofre, cofaqj required = 2 mol of HU x 3.48X10?mol of mol of Na₂CO3 Na Oz = 7.56X10 2 mal Now volume of HCP = 48.0m2 = 48.0m 2x10-3L = 48.0 x103 L - IML Molarity = mole of solute volume of solution in L Molarity = 7.56810 2 mal 48.0 X10-3L I molarity = 1.58m ] for m= mal}. Molarity of HCl solution = 1:58M.