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please help me answer 1-3. My avergae number of mL of 0.100M NaOH required to titrate the remaining anount of HCl in my sample is 1.08mL.
CAMERY Review Layout References Mailings Wednesday, March 25, 2020 View Help ID Number Experiment 17: Analysis of an Antacid
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Answer #1

25 mL 0.1 (M) HU was added, ie 0.0025 molttu. x Excess Hel is consumed by 1.08 ML 01 (1) Naoh. 0 0.2_ x 1.08 mol de. 1000 = 1

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