Question

calculate the enegrry of a photo. of electromagnetic radiation that has a frequency of 1.5x10^18 Hz

due tomorrow!

Answer 1

We can use either the formula E=hf Or E=hc/$\lambda$ , since f=c/$\lambda$.

Here h is the plank's constant.

f is the frequency

c is the speed of light

$\lambda$ is the wavelength of radiation.

In question frequency of radiation is given. So we can use the first equation E= hf

Erbf.: by plank's constant =6.626710- f> frequency An question, it is given that, f = 1.5 x1018 Hz ... The energy of photon = bf = 6.626xI/F:$x 15 x10* ! = 9.939x1016) [ Remember that Hz = 5'7