Question

Which correctly arranges the following aqueous solutions in order of decreasing freezing point? a) 0.01 m K3PO4 > 0.02 m CaBr2 > 0.015 m KCl > 0.015 m CH3COOH b) 0.015 m CH3COOH > 0.015 m KCl > 0.02 m CaBr2 > 0.01 m K3PO4 c) 0.02 m CaBr2 > 0.01 m K3PO4 > 0.015 m KCl > 0.015 m CH3COOH d) 0.015 m CH3COOH > 0.015 m KCl > 0.01 m K3PO4 > 0.02 m CaBr2 e) 0.015 m KCl > 0.015 m CH3COOH > 0.01 m K3PO4 > 0.02 m CaBr2

Answer 1

particles ATf - kfm y Molality of Salute - freezing point temp. a) 0.01 m kapou to 0.02 m Cabrz (50.015 m kao 0.815 m CH3Crot 0.03m kt +0.0lmpo 3- - 8.02m Ca 2+ - 0.04 mbr 0.01smkt +0.015mce- 70.615 CHCE- >0.015 in + 0.04sm particies ooem particles 0.630 m particles 20.030m pontiche arrangement should be 0.02m Ca Bra <0.00 m kg pou <0.015m kee <0.015m chlooh Nta vo Po4 , C@ex, с ате то elect red, tw, CH3COOH weak electrolyte. So, option (d) is the right answer.