The answer will be (b) Potassium is oxidised and Magnesium is reduced.
As oxidation state of magnesium in the reactant side is +2 and in the product side it is 0 so form this we can conlude that magnesium is reduced.
Oxidation state of potassium in the reactant side is 0 as it exist in solid form and the oxidation state in the product side is +1 which is in aqueous state. From here we can conclude that potassium is getting oxidised in the reaction as it oxidation state is increased.
In the Oxidation-Reduction reaction below: 2K(s) + Mg2+ (aq) --------> 2K+ (aq) + Mg(s) (d) Magnesium...
Consider the following reduction/oxidation reaction : Mg(s) + Br2(l) → Mg2+(aq) + 2Br–(aq) What is the anode? a.) Mg(s) / Mg2+(aq) b.) Br2(l) / 2Br–(aq)
Consider the following unbalanced equation. Pb(s) + Mg2+(aq) right --> Mg(s) + Pb2+(aq) (a) What are the following standard voltages? Include the sign, changing it as appropriate. Use the standard reduction potentials in the Reference Tables. Enter the number of decimal places allowed by the data in the table. -standard oxidation potential for the oxidation half-cell: ___ V -standard reduction potential for the reduction half-cell: ___ V -potential for the entire cell:___ V (b) Select all that apply for the...
Magnesium ions and sulfate ions have the following reduction and oxidation reactions and potentials: Mg2+(aq) + 2e– →Mg(s) Eo = –1.18 V 2SO42–(aq)→S2O82–(aq) + 2e– Eo = –2.05 V Why did neither of these half-reactions occur when the magnesium sulfate solution was electrolyzed?
7) In the following reaction, Mg(s) + Cu²+ (aq) → Mg2+ (aq) + Cu (s): A) Mg is the reducing agent and Cu is the oxidizing agent. B) Mg²+ is the reducing agent and Cu is the oxidizing agent. C) Cu is the reducing agent and Mg?is the oxidizing agent. D) Cu²+ is the reducing agent and Mg is the oxidizing agent. E) Mg is the reducing agent and Cuis the oxidizing agent. 8) In the following reaction, Zn (s)...
identification half-reaction Cu(s)— Cu²+(aq) + 2€ Fe3+ (aq) + >Fe²+ (aq) oxidation reduction (2) Write a balanced equation for the overall redox reaction. Use smallest possible integer coefficients.
What element is being oxidized in the following redox reaction? Mg2+(aq) + NH4+(aq) → Mg(s) + NO3(aq) A. O B. H C. N D. Mg
What is the Eºcell, AG', and K for the following reaction? 12(s) + Mg(s) → Mg2+(aq) +2 1. (aq) You must show your work to get credit. Reduction Half-Reaction E° (V) 12 (s) + 2 e- →21 (aq) +0.535 Mg2+ (aq) + 2 e- Mg(s) -2.37 Which compound is being reduced in the following reaction: H2O2 (aq) + 2 Fe2+ (aq) + 2 H3O+ (aq) → 2 Fe3+ (aq) + 4 H20 (1)
Balance the following oxidation-reduction reactions using the half-reaction method. 1. HCOOH (aq) + MnO.. (aq) → CO2 (g) + Mn2. Acidie solution Identify the reduction half Identify the oxidation half Basic solution Identify the reduction half Identify the oxidation half Write a balanced equation for the electrode and overall cell reactions in the following galvanic cell and determine E°. Sketch the cell, labeling the anode and cathode and showing the direction of electron and ion flow. 2. 3. Circle the...
Figure out whether the balanced chemical reaction shown below
involves oxidation reduction. If it does figure out which element
becomes oxidized by the reaction and which element becomes reduced
by the reaction. Pick the correct statement about
this reaction from the multiple choices.
4 KMnO4(aq) + 5 CH3OH(aq) + 12 HCl(aq)
4 MnCl2(aq) + 5 HCO2H(aq) +
4 KCl(aq) + 11 H2O(l)
a) This reaction is not a redox reaction.
b) In this reaction H becomes oxidized and Cl becomes...
Question 1: Consider the following oxidation-reduction reaction: I−(aq)+Cu+(aq)→IO4−(aq)+Cu(s) A: What are the initial and final oxidation states of iodine? B: What are the initial and final oxidation states of copper? C: What element is reduced? D:What is the reducing agent? E: What element is oxidized? F: What is the oxidizing agent? G: Give the atom- and electron-balanced oxidation half-reaction occurring in acidic solution. Express your answer as a chemical equation. Include all phases. H: Give the atom- and electron-balanced reduction...