Question

When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced. CaCO,(s) + 2 HCl(aq) +CaCl, (aq) + H,O(1) + CO2(g) How many grams of calcium chloride will be produced when 27.0 g of calcium carbonate is combined with 15.0 g of hydrochloric acid? mass of CaCl,: 24.3 Which reactant is in excess? O Caco, Онсі How many grams of the excess reactant will remain after the reaction is complete?

Answer 1

Caco3 present in excess
Caco3(8) + 2Hulaq) - Cache lou) +12010) + (0218) given mass of CaCO₃ = 27.09 molar mass of CaCO3 = molog CaCO3 = given mass molar mass = 270g = 0.27moll 100 g mor! mol JHCl = 15.09 = 0.411 mol 36.5 g mor! 1 mola a Co3 яая юј, 2 тој на 0:27 mol g G com react with oosy moluce But mol 7 HCl = 0.411 mol and mol ghal sepüred = 0:54 so Hel is linting reagent and consume completely and reaction proceed according to ha 2molice produced Imol Cacha onull mol he produced o. 2os's mol cacla molar mass of Cach₂ = 110.96 6 mang cauza mol x molar mass :=110.98 man of cache= 22.8 g He is linting reagent X 0.2055 enot = 22.89 hol

2 mol He rest I mol Cacoz 0.ull mol ha react 0.2055 mol cacoa op 403 . mol g ca coz lekt = 0.-020539 = 0.0645 mol mol y Cacos left = 0.0645 mai man oy excess reyent = 0.0645 601 xloog – 6.45 g Anowe