Question

9. (12 pts) Answer parts a-b for the following reaction: Hos?(aq) + 2 Ag(s) = Hg () + 2 Agt(aq) a) Calculate the equilibrium


Ecele = Fired (reduced) - Ered (oxidized) (no need to flip signs!) E = pº In QC q=1.t 1 C = 1 A-s F = 96485 C/mole e R = 8.31
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& = EC-FA 02xou - 0.851- 0.80 od 12 o Hp2 se u = d.osiv ) s6 = nFe = - RT enkelte el 2 - 2x 96485X0.051 = - 8.314 x310xik K=[

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9. (12 pts) Answer parts a-b for the following reaction: Hos?"(aq) + 2 Ag(s) = Hg...
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