Question

4+1+1 = 6 e) (NH4)2(RhCle] f) (Co(en)?(H20)Br]Br2 g) Mg[Cu(H2O)2(C2O4)2] h) Zn[PtCle]

Name each of the coordination compounds

Answer 1

Answer:

(e) (NH4)3[RhCl6] = Ammonium hexachloro rhodate (III).

​​​​​​( First, we name cation ,which is ammonium ,then we name anion part ,in which ,first writing ligand with -O suffix ,and then writing metal name with -ate suffix with the oxidation number in bracket (). )

(f) [Co(en)2(H2O)Br]Br2 = Aqua bromo bis-(ethylenediamine) Cobalt (III).

{ Name cationic part first, in which you should write ligand as per alphabetical order , also, en is a bidentate ligand so we used bis as prifix and then, write the metal name with it's oxidation number}

(G) Mg[Cu(H2O)2(C2O4)2] = Magnesium diaqua bis-(oxalato)cuprate (II)

{ Write cationic part first, cation is Magnesium then , write ,ligand as per alphabetical order, however, oxalato is bidentate ligand so we have used Bis as prefix, then metal name with -ate suffix and with oxidation number}

(F) Zn[PtCl6] = Zinc hexachloro platinate (IV)

(Write cationic part first, then ligand with hexa as 6 Cl are there, and then the metal with it's oxidation number)

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