Question

ADT24_04 The anti-cancer drug m-THPC has an e of 22,400 M cm at 652 nm in methanol. If I put a methanol solution of m-THPC into a 25.0 mm pathlength cuvet, and observe an absorbance of 0.312 (no units) at 652 nm, what is the concentration of the solution? (Assume there are no other solutes present in the methanol.) Select one: 2.3.17(109 b. 4.46 (109) c. 5.57 (10% d. 1.39 (109) • .6.62 (10) Previous page Next pag Jump to... Return to: 520 CLAB 124-00...

Answer 1

Given & for anti cancer drug m-THPC = 22400Mlem! bath length (1) = 25 mm = 2. 5cm absorbance (A) = 0.312 " A=&dc (where 'C' = concentration of solution} =) 0.312= 22400 Mtemt x 2.5cm XC ice 0.312 22400 Mtemtx 2.5cm - 5.57810-6 M so, concentration of solution = 5:57x100M anned with CamScanner C