Question

2 HgO(s) + 2 Hg(s) +0,() what mass of mercury(II)oxide, HgO, would be required to produce 865 L of oxygen, Og, measured at STP? mass bout us Cont cypolicy terms of use contact us ADAM

Answer 1

Page No. Date Answer Given reaction is, i 2 Hgocs) -> 2H9CS) + 02 (9) From the reaction, it is clear that 2 moles of Hgo produces one mole of 02 at STP We know that, one mole of Og contains 22.4 L Therefore ige? mole of Oz contains 865 1 OF O2 -2 . 865 22.4 38.616 meie Of02 -'. 865 1 Of O2 contains 38.616 mole of 02 since, i mole of Oz contains 32 gram of Oz . Therefore, 38.616 mole of a contans 1235, 71 gram of Oz From the reaction, 433 9 of Hgo cgeg Of HgO produces produces 32 9 of 02 1235.71 g of 02 1. L a 1235-71 x 433 32 16727.71 g

Page No. Date + 16 727 71 gram je 16.73 Kg OF HOO require to produce 865 Lt Of O2