Question

AGO/kJ mol -109.7 378.5 -10.8 - 1576.4 0.0 3.1 -604.2 -1128.8 0.0 2.9 Compound AgCl(s) AgN,(s) Ag,O(s) Al2O3(s) Bre(2) Bre(g)Consider the reaction: CaCO3(s) + Ca(s) + CO2(g) Calculate the standard Gibbs free energy of this reaction and the equilibriu

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Consider given reaction, CaCO3 (s) 1585599136669_blob.png CaO (s) + CO2 (g)

For above reaction , standard Gibbs energy change is calculated by using formula as shown below.

1585599136355_blob.pngrG 0 = 1585599136592_blob.png1585599136595_blob.pngfG 0 ( products ) -  1585599136678_blob.png1585599136285_blob.pngfG 0 ( Reactants)

1585599136367_blob.png1585599136552_blob.png1585599137399_blob.pngf G 0 ( products ) = 1585599136943_blob.pngfG 0 CaO (s) +  1585599136370_blob.pngf G 0 CO2 (g)

1585599136373_blob.png1585599136937_blob.pngf G 0 ( products ) = ( - 604.2 k J / mol ) + ( - 394.4 k J / mol ) = - 998.6 k J / mol

1585599136678_blob.png1585599136285_blob.pngfG 0 ( Reactants) = 1585599136943_blob.pngfG 0 CaCO3 (s) = - 1128.8 k J / mol

1585599136367_blob.png1585599136355_blob.pngrG 0 = - 998.6 k J / mol - ( - 1128.8 k J / mol) = 130.2 k J / mol

We have relation, 1585599136355_blob.pngrG 0 = - 2.303 R T log K , where K is equilibrium constant.

At standard conditions, T = 298 K .

1585599136367_blob.png 130200 J / mol = - 2.303 \times 8.314 J K -1 mol -1 \times 298 K \times log K

log K = - (  130200 J / mol / 2.303 \times 8.314 J K -1 mol -1 \times 298 K )

log K = - 22.82

Taking antilog on both sides, we get K = 1.52 \times 10 -23  

ANSWERS 1) 1585599136355_blob.pngrG 0 = 130.2 k J / mol and 2) K = 1.52 \times 10 -23  

Add a comment
Know the answer?
Add Answer to:
AGO/kJ mol -109.7 378.5 -10.8 - 1576.4 0.0 3.1 -604.2 -1128.8 0.0 2.9 Compound AgCl(s) AgN,(s)...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT