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Assume a 3.0 mass % aqueous solution of compound that has molar mass of 74.44. (Assume the density of water at this temperatu

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Part-A of Givenas Mass 080 = 3.00). Molar mass= 74.44 g/mol 3.0 mass of of solution, which means each 100g solution containsmolality= 0.4155 mol/kg molality = 0.42 m Ang Part-B W mole fraction of compound = no. of mole of compound no. of mole of com

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