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A 36.23g sample of a substance is initially at 25.5 degrees C. After absorbing 1759 J...

A 36.23g sample of a substance is initially at 25.5 degrees C. After absorbing 1759 J of heat, the temperature of the substance is 115.6 degrees C. What is the specific heat of the substance?

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Answer #1

= 90.1 °C Calculating Specific heat: mass of substance = m = 36.23 g Specific heat of substance = S = ? J/g°C Temperature dif

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