Show one sample calculation to convert from % mass to molality.
This is a ethylene glycol solution.
Mass % Ethylene glycol= 2.00, molality=0.32
mass %: 2= (0.50/25.01)x100
molality: 0.32=(0.50 x (1/62.06)) / ((25.01-0.50) x 1/1000)

Show one sample calculation to convert from % mass to molality. This is a ethylene glycol...
Show one sample calculation to find the Tf for a 52.0% mass solution (again, use the trendline from the molality graph). (Hint: convert 52.0% to correct units!) The equation is Tf=0.485(m)+-0.134 where Tf is freezing temperature and m is molality. I'm guessing you have to convert percent mass to molality but I don't know how to do that. EDIT: It is a Ethylene glycol solution, so molar mass is 62.06.
What is the molality of ethylene glycol, C2H4(OH)2, in a solution prepared from 2.22 × 103 g of ethylene glycol and 2.00 × 103 g of water?
What is the molality of the 55.0 mass % ethylene glycol (C2H6O2) solution in the water used for automobile antifreeze?
15. What is the molality of a solution made from 1 gal of ethylene glycol (density 1.11 g/ml) and I gal of water (density 1.00 g/ml)? 4 pts 16. Determine the freezing point and boiling point for the aqueous solution in number 15 above. Water is the solvent. 4 pts
A solution of ethylene glycol in water at 20 degrees celsius has a mass percent of 9.78% of ethylene glycol with a density of 1.0108 g/mL. The freezing point depression constant for water (solvent for all solutions) is Kf=-1.86 percent celsius kg/mol and the boiling point elevation constant is Kb=0.512 degrees celsius kg/mol. The density of neat water at 20.0 degrees celsius is 0.9982 g/mL. Answer the following: 1. What is the molarity of the solution? 2. What is the...
A solution of ethylene glycol in water at 20.0°C has a mass percent of 8.25% of ethylene glycol with a density of 1.0087 g/mL. The freezing point depression constant for water (which you can assume is the solvent for all solutions) is K1.86°C kg/mol and the boiling point elevation constant is Kb the following: 0.512°C kg/mol. The density of neat water at 20.0°C is 0.9982 g/ml. Answer 1. What is the molarity of the solution? 2. What is the molality...
Antifreeze is ethylene glycol, C2H4(OH)2 and is made from ethylene which is produced from oil. It is miscible in water (i.e., dissolves in any proportion), does not dissociate in water, is toxic to drink (especially to dogs who like the sweet taste), but fortunately is biodegradable and at normal automobile operating temperatures, is not flammable. It can prevent freezing of the automobile cooling system down to -34oF and the advertisement says “winter - summer automobile coolant” — it also prevents...
2. Calculate the concentrations of solutions 1-7 from the procedure step 2. Show one sample calculation. Test Tube # Concentration (M) 2. Prepare one solution at a time by pipeting the following volumes into a small beaker for mixing, then transfer the solution to the appropriate test tube. Test Tube No. 0.150 M COCI, (m.) 2.00 4.00 5.00 6.00 7.00 8.00 10.00 Distilled H,O (mL) 8.00 6.00 5.00 4.00 3.00 2.00 0.00
i need help using the formula in the 3rd picture , to figure
picture 2(the molar mass). I included needed information in picture
1
Pure TBA, T9 Ethylene Glycol/TBA Solution, T Calculation of Molar Mass of Ethylene Glycol Mass of ethylene glycol used (total amount in solution) .94 253 t Mass of TBA used Freezing point of pure TBA, T Freezing point of solution, T, oC oc oC Freezing point depression (total dgpression), 471 Total molal concentration m of ethylene...
26.)Show the calculation of the mass of NaNO3 needed to make 450 ml of a 0.356 M solution. 25.)Show the calculation of the molarity of a solution made by dissolving 15.9 grams of Ca3(PO4)2 to make 350 ml of solution. 24.)Show the calculation of the molarity of a solution made by dissolving 12.6 grams of NaNO3 to make 200 ml of solution. 23.Show the calculation of the molality of a solution made by dissolving 15.9 grams of Ca3(PO4)2 in 400...