Question

Question completion Status QUESTION 7 The solubility product of calcium chromate is 7.10x10 4. If you were to put 0.040 moles of calcium chromate into 2.00 L of water and allowed the system to equilibrate, would you expect to see any remaining solid salt in the beaker? Yes, because the system is super saturated. Yes, because the system is oversaturated. No, but the system is fully saturated. I No, because the system is not yet saturated

Please answers these 3 questions. Thank you!!

Answer 1

0 [cac7047 = mc) = 0.090 mo) - 0.0207 volume 2.00L © Cacro(s) z Cort(@a) + Croy2799) Kspa 7.10X10 4 [ca2+] = [crog 2-] = 0.020m. a= [cart] [coroa 2-] = (0.02012 = 4:0 x 10-4 Aq s < KSP ; So No, because the systems is not yet saturated ARY (5) = A3time) + 3B aa) I CA3+] = 1.01 X1010m : [B-] = 3x[A3+] = 3x1.01x10lom Ksp = [A3+] CB-7² = 3.03 xlo-lom - 11.01x1010) (3.03 x1070)3 = 2.79 X10-39 Langava) the poq Ž Mt (aa) + H2 rog (aa) kal H₂Pog-laa) ² Ht laa) + Mpod 2 laa) Kaz Hpog 2 laa) & utlaa) + poq3 laa) Kaz opron: 3 pootenaton platex pka 27 pkai 000 290 11 11