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Suppose 1.30 g of NaNO2 is added to enough 0.20 M HNO2 to make exactly 50...

Suppose 1.30 g of NaNO2 is added to enough 0.20 M HNO2 to make exactly 50 mL of solution. What is the expected pH of the resulting solution? How do I know what the Ka for this problem is? Do I need to look it up in my textbook?

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Answer #1

Solution males of NaNO2 z 1.30gm molare mass of NONO 2 2 1.3ogus = 0.01884 wall 68.ggn holl Ka CHNO2) is not given in questio

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