Question

In the laboratory, you dilute 3.61 mL of a concentrated 12.0 M hydrochloric acid solution to a total volume of 175 mL. What is the concentration of the dilute solution?

Answer 1

Moles(n)= Molarity(M) ~ Volume(V) Number of moles before neutralization = after neutralization Mix V1 = M2 x V2 Mi = initial Molarity = 12.0 M Vi = initial Volume = 3.61 mL M2 = diluted Molarity = ? M V2 = diluted Volume = 175 mL Mi xV1 = Ma XV2 12.0 x 3.61 = M2 x 175 43.32 = M2 X 175 M2 = 0.248 M M2 = diluted Molarity = 0.248 M M2 = diluted Concentratin = 0.25 M