Calculate the amount of Fe(NH4)2(SO4)2·6H2O needed to make 250mL of a 0.002M iron solution. (2 points)

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Calculate the amount of Fe(NH4)2(SO4)2·6H2O needed to make 250mL of a 0.002M iron solution. (2 points)

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Answer 1

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2 Fe (NH4) (304) 6H2O stands for Ammonium iron (11) sulfate or Mohips salt. To find the amount or massgjoj- Mohrs salt need Now, Moles of solution - Mass of solute Мо ал. Молл - O solute . molar Mass of Fe (NH4), (S04):6H20 = 284.05 g/mol. Given We

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Calculate the amount of Fe(NH4)2(SO4)2·6H2O needed to make 250mL of a 0.002M iron solution. (2 points)

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Calculate the amount of Fe(NH4)2(SO4)2·6H2O needed to make 250mL of a 0.002M iron solution. (2 points)

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Calculate the mass amount of Fe(NH4)2(SO4)2•6H2O needed to prepare 100mL 1000mg Fe/L stock solution?

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1.1 Accurately (using an analytical balance ONLY) weigh 1.4 g of Fe(NH4)2(SO4) 2-6H20 1.2 Dissolve in...

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Calculate the amount of Fe(NH4)2(SO4)2·6H2O needed to make 250mL of a 0.002M iron solution. (2 points)

Homework Answers

Add Answer to: Calculate the amount of Fe(NH4)2(SO4)2·6H2O needed to make 250mL of a 0.002M iron solution. (2 points)

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Calculate the amount of Fe(NH4)2(SO4)2·6H2O needed to make 250mL of a 0.002M iron solution. (2 points)