The first three ionization energies for element Z are 320 kJ/mol, 640 kJ/mol, 10,200 kJ, mol. What is the likely charge of Z
Z+
Z2+
Z3+
Z4+
The first three ionization energies for element Z are 320 kJ/mol, 640 kJ/mol, 10,200 kJ, mol....
Question 1 (1 point) If the first four ionization energies of an element Z are 483, 5038, 10120, and 15640 kJ/mol. What is the most likely formula for the stable lon of Z OZ Oz* Oz2+ Oz2- Oz3+
82. A period three element has 738, 1451, and 7733 kJ/mol as its first three ionization energies. What is the symbol of this element?
please explain why
3. The first six ionization energies (kJ/mol) of a certain SECOND-ROW element are as follows: Ij = 1,086 12 = 2350 13 = 4620 14 = 6220 Is = 38,000 16 = 47,261 The most likely identity of this element is a) B b) 0 c) N d) Be e) C
Which element is most likely to have the following ionization energies: I1 = 549 kJ/mol I2 = 1,064 kJ/mol I3 = 4,138 kJ/mol I4 = 5,500 kJ/mol A) K B) Sr C) Cs D) S E) Al
Consider this set of ionization energies. IE1 = 578 kJ/mol, IE2 = 1820 kJ/mol, IE3 = 2750 kJ/mol, IE4 = 11,600 kJ/mol. To which third-period element do these ionization energies belong?
15. Below is a list of successive ionization energies (in kJ/mol) for a period 3 element, X. What is the most likely formula for a stable ion of X? 151 = 1000 IE2 = 2250 IE3 = 3360 IE4= 4560 E5= 7010 TE6= 8500 IE2 = 27.100 d. X a. X2 b. X30 c. X²
a new element X is discovered that has the following successive ionization energies (kj/mol) IE1=1004 , IE2=1251 IE3=5988 , IE4=6220 , IE5=6803 , IE6=7178 a. what group (column) do you expect this element will belong? explain b. if this element X combined with fluorine , what is the likely molecular formula?( for example XF2, X2F3, etc)
9. A certain 4th row element has the following ionization energies: 12 = 1310 kJ/mol I3 = 2652 kJ/mol 14 = 4175 kJ/mol Is = 9581 kJ/mol 16 = 11533 kJ/mol Now tell me, most peerless predictor of periodic properties, what is the identity of the element? Please provide an explanation as well.
4. Consider an element of Period 2 which has the following successive ionization energies, in kJ/mol. What is the charge of the common ion? IE1, 1314 IE2, 3389 IE3, 5298 IE4, 7471 IEs, 10992 IE6, 13329 IE7, 71345 IE8, 84087 (1) -1 (2) –2 (3) –3 (4) +6 (5) +7
Identify the group number of the element that has the following successive ionization energies (in kJ/mol). E1 = 1,060 IE2 = 1,890 IE3 = 2,905 IE4 = 4,950 IE5 = 6,270 IE6 = 21,200 IE7 = 25,400