Question

you prepare a solution of CH3OH by dissolving 29.3g of CH3OH in enoigh water to make a 230Ml solution what is the concentration in molarity of your prepared

solution

Answer 1

Answer – We are given,

Mass of CH3OH = 29.3 g

Volume of Solution = 230 mL

We asked for a concentration in molarity. To determine the molarity we need moles and volume in L.

The moles of CH3OH –

We know the formula,

  

Given mass Moles = Molar Mass

By plugging the values,

  

Moles of CH2OH(9) = 29.3 9 CH2OH(9) -= 0.914 moles . 32.04 not

The Molarity of CH3OH –

We know the formula,

  

Moles Molarity – Volume(L)

The volume in L –

We know, 1 mL= 0.001 L

So 230 mL = 0.230 L

  

0.914 moles (CH2OH) = 0.230 L -= 3.98 M

Thus, the concentration of CH3OH in molarity is 3.98 M