Question

94.20 mL of 0.800 M potassium hydroxide reacts with 125.0 mL of a solution

containing oxalic acid, H2C2O4, which is a diprotic species. What is the concentration of

the acid solution?

Answer 1

To find the concentration (molarity) of the acid solution Given that 94.20 mL of 0.800 M potassium hydroxide 125.0 mL of oxalic acid(H,C,0) Potassium hydroxide (KOH) reacts with oxalic acid to produce potassium oxalate (K,C,0) and water chemical equation 2KOH+H2C2O4 →K,C204 +2H,0 First find the moles of KOH moles = molarity x volume 94.20 mL = 0.0942L moles = 0.800mol/L 0.0942L = 0.07536moles Findthe moles of H,C,04 According to reaction H, C,0, and KOHis1: 2 mole ratio Imole of H,C,04 Therefore moles of H,C,04 = 0.07536moles of KOHX- 4- = 0.03768moles H,C204 2moles of KOH To find the concentration (molarity) of the acid solution moles of solute Molarity = liters of solution 125.0mL = 0.125L 0.03768m oles Molarity = 0.125L = 0.3014M Hence the concentration of the acid solution = 0.3014M|