Question

Question 6 1 pts In the reaction of magnesium chloride with sodium phosphate, how many grams of magnesium phosphate are expected when 50.0 g MgCl2 and 75.0 g Na3PO4 are reacted? 3 MgCl2 (aq) + 2 Na3(PO4)2 + Mg:(PO4)2 (8) + 6 NaCl(aq) How should you solve this problem? Decide which reactant has more grams and use that to calculate the amount of product formed Perform separate and complete stoichiometric evaluation for each reactant. Determine which produces most product and report it as the amount produced Perform separate and complete stoichiometric evaluation for each reactant. Determine which reactant produces the least w the munduced

Answer 1

Balanced equation. + 2N03(PO4)2 lag) 1993 (P04/2 181 + 6Nocl lag! 3 MgCl2 (aq) molar meu 95.21 linglmoll 58.44 nawag 259.90 262.86 3 moles of MgCl2 produce I mole of M93 (P04/2 3x95.21 g of MgCl2 produce 262.86 g of mg 3(PO4)2 50.og of Mach produce Mg3(PO4)2 = 262,869 x 500g 3x95.219 = 46.019 mg 3 (P04/2 & mola of Na3(PO4)2 produce I mole of Mgo (Poul2 &X 258.90g of Nas (Pouls produce 262186g of M93(PO4)2 =) 75.0 g of NQ3 (Poul produce Mg3(PO4)2 = 262.869 X75.0g 2 x 258.909 = 38.079 Mg3 (104/2 Hence, the maximum mass of product (ng> (PO4)2 ] that can be formed is 38.079 Answer To solve this problem. Perform separate and complete storchiometric Determine which reactant produce the least as the amount produced evaluation for each reactant. product and report it Hence, option I is correct Please Rate