ASAP!
What is Ka for the weak acid, HA, if a 0.020
M solution of the acid has a pH of 3.29 at 25ºC?
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a. 5.1 × 10-2 |
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b. 6.9 × 10-2 |
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c. 2.6 × 10-4 |
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d. 1.3 × 10-5 |
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e. 1.0 × 10-6 |
What is the conjugate acid of H2PO4–(aq)?
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a. H3O+ |
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b. H3PO4 |
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c. HPO42– |
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e. PO43– |
![th 0 HA (aq) + H20 (1) = Ā (ae) + H2O (aq) I 0.020 0 0 c -a E (0.020-0) Ka = [a) (wzot) min [la] (0.020-n) Given, pH = -log](http://img.homeworklib.com/questions/644c4f90-debe-11eb-b7e9-156d23d30f8e.png?x-oss-process=image/resize,w_560)
ASAP! What is Ka for the weak acid, HA, if a 0.020 M solution of the...
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