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If 242 mL of a 2.50 M aqueous solution of Ca(NO3)2 is evaporated to dryness, what...

If 242 mL of a 2.50 M aqueous solution of Ca(NO3)2 is evaporated to dryness, what is the mass of the residue?

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Concentration of Ca(NO3), = 2.50M = 2.50 mo! . . L Volume of the Ca(NO3), solution = 242 mL X: solution = 242 ML * 1000 mL =0

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