Question

Report Sheet - Lab 30A-3 Calculate the number of moles of magnesium that will react in each flask by comparing the number of moles of magnesium in the flask with the number of moles of magnesium that will react with the HCI. Since 2 moles of HCl are required for each mole of magnesium, the number of moles of Mg with will react with 0.05 moles of HCl is 0.05 moles HCL x (1 mole Mg/2 moles HCI) = 0.025 moles Mg. Compare the moles of magnesium with the moles of magnesium that will react with HCl. The smaller value is the number of moles of magnesium that will react in that flask. Circle the number of moles of magnesium that will react in each flask a. Number of moles of Mg in 0.3 grams flask al. Number of moles of Mg which will react with 0.05 moles HCI b. Number of moles of Mg in 0.6 grams flask bl. Number of moles of Mg which will react with 0.05 moles HCI c. Number of moles of Mg in 1.2 grams flask cl. Number of moles of Mg which will react with 0.05 moles HCI Questions and Problems Q.3 Why is the number of moles of HCl divided by 2 when it is compared to the number of moles of magnesium for determining the limiting reactant?

Answer 1

I Given : Reaction blu magnisium and He can be written as Mg + 2HCl - Mach & the 1. Imole of Mg require a moles of Hal to produce products. Sol" mous - mass molar mass a Number of moles of Mg in 0.39 flask = 0.39 = 0.0123 moles My ai I mole of Mg reacts with a moles of Hell n mole of Mg reacts with 0.05 moles of Hel = x= 0.05 = 0.025 moles of my 0.025 moles of Mg required to reacts with 0.05 moles of Hcl but available is only 0.0123 moles of Mq. Hence ng is the limiting reagent. : 0.0123 moles of Mg reacts with 0:05 moles of Hel.