
the kenetic energy (j) of a single electrom moving at 7.65x10^6 m/s is
11. The kinetic energy of an 80-kg object moving at 10 m/s is 2000 J 4000 J 6000 J 100 J 1000 J 12. The kilowatt-hour is a unit of speed power force momentum energy 13. Energy sources used today (in the U.S.) are, mostly, from: hydroelectric dams solar panels nuclear power stations geothermal sources fossil fuels 14. What is the velocity of a 30-kg box with a kinetic energy of 6,000 J? 64 m/s 6.0 m/s 18 m/s 20...
What is the kinectic energy of a proton moving at 1.40 x 10^6 m/s? How about a 1300 kg car moving at 60 mph?
A railroad car with a mass of 1.95 ✕ 104 kg moving at 2.88 m/s joins with two railroad cars already joined together, each with the same mass as the single car and initially moving in the same direction at 1.56 m/s. (a) What is the speed of the three joined cars after the collision? m/s (b) What is the decrease in kinetic energy during the collision? J
A railroad car of mass 2.95 ✕ 104 kg moving at 3.10 m/s collides and couples with two coupled railroad cars, each of the same mass as the single car and moving in the same direction at 1.20 m/s. (a) What is the speed of the three coupled cars after the collision? m/s (b) How much kinetic energy is lost in the collision? J
A railroad car of mass 2.45 ✕ 104 kg moving at 3.05 m/s collides and couples with two coupled railroad cars, each of the same mass as the single car and moving in the same direction at 1.20 m/s. (a) What is the speed of the three coupled cars after the collision? m/s (b) How much kinetic energy is lost in the collision? J
A certain moving electron has a kinetic energy of 1.01 × 10−19 J. A. ) Calculate the speed necessary for the electron to have this energy. The mass of an electron is 9.109 × 10−31 kg. Answer in units of m/s. B.) Calculate the speed of a proton having a kinetic energy of 1.01 × 10−19 J and a mass of 1.673 × 10−27 kg. Answer in units of m/s.
We learned in class that the kinetic energy (KE) of an object with mass m moving at velocity v is KE =½ m v^2. Accordingly, the kinetic energy (KE) per unit mass (m) of a body moving at velocity v is KE/m=v^2 /2. What is the asteroid’s kinetic energy per unit mass (J/kg) for an impact at this velocity? State your answer in units of J/kg. velocity is 29.8 km/s
A railroad car of mass 1.85e4 kg moving at 3.14 m/s collides and
couples with two coupled railroad cars, each of the same mass as
the single car and moving in the same direction at 1.24 m/s.
b)
How much kinetic energy is lost in the collision?
USE THIS DATA:
17400 kg; 3.27 m/s; (help me see how you get the correct answer
of 2.39e4 J.
16-4 A railroad car of mass 1.85e4 kg moving at 3.14 m/s collides and...
A railroad car of mass 2.42 × 104 kg is moving with a speed of 3.84 m/s. It collides and couples with three other coupled railroad cars, each of the same mass as the single car and moving in the same direction with an initial speed of1.92 m/s.(a) What is the speed of the four cars after the collision?____ m/s(b) How much mechanical energy is lost in the collision?______J
(1) A moving object has a kinetic energy of 119 J and a momentum with magnitude of 28.0 kg·m/s. (a) Determine the mass of the object. ______ kg (b) Determine the speed of the object. ______m/s (2) A 5.1 g dart is fired into a block of wood with a mass of 24.2 g. The wood block is initially at rest on a 1.6 m tall post. After the collision, the wood block and dart land 3.4 m from the...