Question

A piece of iron is recovered from a murder scene. It is heated to 103.7oC and then put into a calorimeter containing 100.0 mL of water at room temperature, (25.0oC). The temperature of the water increases to 57.8oC. What is the mass of the iron piece?

Answer 1

Information required Density of water = 1.0 g/m2 Cs; Specific heat of Iron = 0.450 Tlgic Cw; specific heat of water = 4.186 Ilg'c Here we have - volume of water = 100.ome Also mass = volume & Density i = 100 ml x 1.0g = 100g # Initial temp. of Iron = 103.7°C. of water = 57.8°C # Final temp. of Iron = final temperature # Initial temp of water = 25°c. let mass of Iron piece be my g 1 - Heat lost by Iron = Heat gain by water - (mCAT) son = (mCAT) water - - - (my x 0.450 x (57.8-103-7)) = (100 x 4.186X ( 57.5-25)) MI = 664.73g Hence, mass of Iron piece = 664.7 g Please Rate ...