The fundamental frequency of an open-open tube is 1367 Hz when thetube is filled with 0°C...

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Question

The fundamental frequency of an open-open tube is 1367 Hz when thetube is filled with 0^°C helium. What is itsfrequency when filled with 0^°C air?

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Answer 1

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Answer #1

fundamental frequency f = v / 2L

i.e. f α v

( f' / f ) = ( v' / v )

given f = 1367 Hz

v' = speedof sound in air = 331 m / s

v = speed of soundin helium = 972 m / s

So, frequency in air f' = fv' / v

= 465.51 Hz

Answer 2

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