Question

How many grams of Al2O3 can be produced from 18.0 g Al?

4Al(s) + 3O2(g) > 2Al2O3(s)

Answer 1

- Ans Griven Reaction is 4A (s) + 30, 19) — 211,0, (s) Using stoichiometsys you a balanced reaction, the coefficient represents the moles of the substance Hence, - 4 Al(s) + 30249) — 2A12 Oz (5) 4 moles 3 moles 2 moles Thust 4 moles of Al. (s) reacts completely with 3 moles 02 Lg) to give 2 moles of AL2O3 Or we can say that 2 moles of Abog is produced by 4 moles of Alls)

molari Mass of Alls) = 27.4m molar mass of Al₂O₂ (s) = 102 gm. Hence 2 mole Ah Oz (s) = 2 x 102 gm 3 204 gm. and 4 mole of Al (s) = 108. gm As 2 moles of Al₂O3 is produced by 4 moles of Alls) Hence, 204 gm of Ala Oz produced by 108 gm of Alls) - 1 gm of Al is) produces 204 gm Aho 204 De 108 u

Criven mass of Al = 18.0 gm Hence Al 18 gm . 108 produces 204 x 18 gm Ala Og = 34 gm Ala Oz Hence, from 34 gm 18 gm Al₂ Oz can be produced Al