Question

What is the ΔrG for the following reaction (in kJ mol-1) at 298 K? 3 O2...

What is the ΔrG for the following reaction (in kJ mol-1) at 298 K?

3 O2 (g) ⇌ 2 O3 (g)

The conditions for this reaction are: PO2 = 1.64 bar

PO3 = 1.28 bar .

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Answer #1

rea B 469 of the reaction 302 (3) 3 903 (3) can be calculated as . 4769 = - RT ln Kp. : o constant at constant equilibecicem: 3769 = -8.314 Jyl mule? * 299k In (0.371) := (= 8.314 x 298% -0.992) Hak Imolei = 4 2456.6 Jmole! 1G = 2.457 kJ mole

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