How many grams of solid sodium
acetate should be added to 1.00 L
of a 0.284 M acetic acid solution
to prepare a buffer with a pH of 5.292 ?
grams sodium acetate
= g.
I have provided the details of the solution. Just go through it.
So 81.12 gm of sodium acetate is added to the solution.
![0.542 = log sa alt] 0.284 & Salt] 10.542 7 0.284 - Salt] = 0.884 3.483 = 0.999 M So 12 of the solution contains 0.989 moles o](http://img.homeworklib.com/questions/2d783960-e062-11eb-bffb-abeef53cdabd.png?x-oss-process=image/resize,w_560)
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