Consider the equilibrium reaction at 100°C:
2NO(g) + O2(g)⇌ 2NO2(g); KC = 30,000
Write the concentration equilibrium equation for the reaction.
If 46 grams of NO2(g) is introduced into a 1 L flask what will be the equilibrium concentrations of NO2, O2 and NO?
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Consider the equilibrium reaction at 100°C: 2NO(g) + O2(g)⇌ 2NO2(g); KC = 30,000 a. Write the concentration equilibrium equation for the reaction. [1 b. If 46 grams of NO2(g) is introduced into a 1 L flask what will be the equilibrium concentrations of NO
2NO2 = 2NO + O2 initially 0.6 NO2 0.46 NO what is the value of kc Initially, 0.600 mol of NO2 is placed in a 1.00 L flask. At equilibrium, the concentration of NO was found to be 0.460 mol/L. is all the information I received
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Part B please
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What are the equilibrium concentrations for the equation 2NO<--> O2 + H2, if the initial concentration of NO is .175M and the KC value is 0.17? Please create an ICE table
For the equilibrium N2(g) + O2(g) <--------> 2NO(g) At 2300K the equilibrium constant is Kc = 1.7 x 10-3. Suppose 0.012 mol NO(g), 0.25 mol N2(g) and 0.35 mol O2(g) are placed into a 7.5 L flask at 2300K a) is the system at equilibrium? b) If not, in which direction must the reaction proceed to reach equilibrium c) calculate the equilibrium concentrations of all three substances
QUESTION 1 (10) Nitric oxide reacts with oxygen to form nitrogen dioxide: 2NO(g) + O2(g) + 2NO2 (g) a) What is the Kc for the reaction if the equilibrium concentration of NO is 0.300 M, O2 is 0.200 M, and NO2 is 0.530 M at 25°C? b) What is the Kp for the same reaction? c) If the equilibrium re-establishes where [NO]=0.150 M and [02]-0.225 M, what is [NO2) at this point under the same temperature? 2(12) The equilibrium constant...
Consider the following reaction: 2NO(g)+O2(g)⇌2NO2(g)2NO(g)+O2(g)⇌2NO2(g) The data in the table show the equilibrium constant for this reaction measured at several different temperatures. Temperature K 400 1.9x10^7 425 2.5x10^6 465 1.6x10^5 515 8.8x10^3 600 2.0x10^2 Use the data to find ΔrS∘ΔrS∘ for the reaction. (answer in J K-1 mol-1) The answer is NOT 158