A light beam travels at 1.34×108 m/s in diamond. The wavelength of the light in diamond...
A light beam travels at 1.34×108 m/s in diamond. The wavelength of the light in diamond is 246 nm
Part A
What is the index of refraction of diamond at this wavelength?
Part B
If this same light travels through air, what is its wavelength there?
Homework Answers
(a)
Let the refractive index of diamond be, n
v = 1.34 * 10^8 m/s
v = c/n
(1.34 * 10^8) = (3.0*10^8)/n
n = 2.24
(b)
f = c/λ
f = (1.34*10^8)/246 nm
f = 544715.5 * 10^-9 Hz
v = f*λ
λ = v/f
λ = (3.0*10^8)/(544715.5)
λ = 550.75 nm
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