Given Bsquare coil =1.13 x 10-4*I (Tesla), what is the value of the horizontal component of...
Given Bsquare coil =1.13 x 10-4*I (Tesla), what is the value of the horizontal component of Earth's magnetic field, Bearth, (in Gauss), if, at a current I= 0.18 A through a tangent galvanometer with a square coil, the angle between Bearth and Bnet is θ=51 degrees? Express the answer (without unit) to two decimal place.
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Given Bsquare coil =1.13 x 10-4*I (Tesla), what is the value of
the horizontal component of...
Data Table One Angle of Inclination ( ф ) Deflection current (l45) - L-60- 201.5mA Turn on the ...
Data Table One Angle of Inclination ( ф ) Deflection current (l45) - L-60- 201.5mA Turn on the power supply and adjust the fine voltage settings until the needle of the compass in the galvanometer is deflected by exactly 45 degrees from north. Use the DMM to determine the circuit current. Record this in Data Table One. Q1: The Biot-Savart integral gives the magnetic field at the center of a closed circle. The tangent galvanometer coils have 20 turns and...
Question 3:9 points Earth's Magnetic Field: The following data were recorded from the horizontal component of earth's magnetic field R: radius of the coil. N: Number of turns experiments....
Question 3:9 points Earth's Magnetic Field: The following data were recorded from the horizontal component of earth's magnetic field R: radius of the coil. N: Number of turns experiments. N 250 turns R 7.5 cm tan Bave I (mA) 2.5 4.2 9.5 14.2 25.5 16 34 45 62 16 32 45 60 a) Fill the table. (2 points) b) Use the data in the table to plot a graph between the current I and tan a (3 points) c) Determine...
What is the length of the side (in cm) of a square coil with N =...
What is the length of the side (in cm) of a square coil with N = 28 turns and current through the coil I = 0.28 A, if the magnetic field at the center of the coil is B = 0.31 Gauss? Express the answer (numerical value only) to one decimal place.
Can someone please help me with D and E. Constants Part A To understand the magnetic...
Can someone please help me with D and E.
Constants Part A To understand the magnetic force on a straight current-carrying wire in a uniform magnetic field. Magnetic fields exert forces on moving charged particles, whether those charges are moving independently or are confined to a current- carrying wire. The magnetic force Fon an individual moving charged particle depends on its velocity and charge er. In the case of a current-carrying wire, many charged particles are simultaneously in motion, so...
ANSWER ALL PLEASE Question 35 2 pts A charged particle (with q = 1.0 x 10-2...
ANSWER ALL PLEASE
Question 35 2 pts A charged particle (with q = 1.0 x 10-2 C) that is moving through a uniform magnetic field has a velocity v = (6.0 x 105m/s) i + (4.0 x 105m/s) k when it experiences a force F due to the magnetic field. If B = (-3.0 x 10-3T)i + (4.0 x 10-3T)j + (5.0 x 10-3T)k, calculate the force, in N (in terms of unit vectors). Equation: F=qvxB OF=-(3.0 N)i - (6.0N)j...
Data Table One Angle of Inclination ( ф ) Deflection current (l45) - L-60- 201.5mA Turn on the power supply and adjust the fine voltage settings until the needle of the compass in the galvanometer is deflected by exactly 45 degrees from north. Use the DMM to determine the circuit current. Record this in Data Table One. Q1: The Biot-Savart integral gives the magnetic field at the center of a closed circle. The tangent galvanometer coils have 20 turns and...
Question 3:9 points Earth's Magnetic Field: The following data were recorded from the horizontal component of earth's magnetic field R: radius of the coil. N: Number of turns experiments. N 250 turns R 7.5 cm tan Bave I (mA) 2.5 4.2 9.5 14.2 25.5 16 34 45 62 16 32 45 60 a) Fill the table. (2 points) b) Use the data in the table to plot a graph between the current I and tan a (3 points) c) Determine...
Can someone please help me with D and E.
Constants Part A To understand the magnetic force on a straight current-carrying wire in a uniform magnetic field. Magnetic fields exert forces on moving charged particles, whether those charges are moving independently or are confined to a current- carrying wire. The magnetic force Fon an individual moving charged particle depends on its velocity and charge er. In the case of a current-carrying wire, many charged particles are simultaneously in motion, so...
ANSWER ALL PLEASE
Question 35 2 pts A charged particle (with q = 1.0 x 10-2 C) that is moving through a uniform magnetic field has a velocity v = (6.0 x 105m/s) i + (4.0 x 105m/s) k when it experiences a force F due to the magnetic field. If B = (-3.0 x 10-3T)i + (4.0 x 10-3T)j + (5.0 x 10-3T)k, calculate the force, in N (in terms of unit vectors). Equation: F=qvxB OF=-(3.0 N)i - (6.0N)j...
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