Question

A freshly cooked potato is cooling on a plate. The temperature of the potato is observed...

A freshly cooked potato is cooling on a plate. The temperature of the potato is observed to drop by 5 oC in the first minute of cooling. Will it cool by more or less than 5 oC in the second minute?

0 0
Add a comment Improve this question Transcribed image text
Answer #1

The heat lost by the potato = mass x specific heat x change in temperature

Since the change in temperature with respect to room temperature decreases everytime with passing minutes , the amount of energy released will also be less. In such a case if the temperature dropperd by 5oC in the first minute of cooling , so the potato will cool less than 5oC in the second minute.

Add a comment
Know the answer?
Add Answer to:
A freshly cooked potato is cooling on a plate. The temperature of the potato is observed...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Newton’s Law of Cooling states that the temperature of an object changes in time according to...

    Newton’s Law of Cooling states that the temperature of an object changes in time according to the equation dT =k(E−T)dt where T(t) is the temperature of the object, E is the temperature of the environment surrounding the object and k is a constant that is determined by the physical properties of the object. The value k can be expressed as k = hA , ρV cp where h is the heat-transfer coefficient (a measure of how quickly heat escapes the...

  • Exercise 1.18 A freshly forged flat steel ( λ-56, 16 W/m K , c.-450 J/kg K, ρ-7800 kg/m2 ) is immersed in an oil bath at 800°C. The steel surface immediately reaches the temperature of the oil ba...

    Exercise 1.18 A freshly forged flat steel ( λ-56, 16 W/m K , c.-450 J/kg K, ρ-7800 kg/m2 ) is immersed in an oil bath at 800°C. The steel surface immediately reaches the temperature of the oil bath of 50°C. Neglect marginal effects and consider the steel as a plate with a thickness of 10 mm. What are the steel temperatures in 1 mm, 4 mm and 5 mm below the surface? a) after 1/100 second? b) after 1/10s c)...

  • 2. A 250.0 mL container of gas is at 150.0°C. At what temperature will the gas...

    2. A 250.0 mL container of gas is at 150.0°C. At what temperature will the gas occupy a volume of 125 mL? (assume constant pressure) puulle Will the gas Dulle constant pressure) 3. An open flask of air is cooled. a. Does it contain more gas molecules before or after cooling? b. is the pressure the same, greater or less than before it was cooled? b. Is the pressure the same, greater or less than before it was cooled? 4....

  • not the firsf picture. only the second QUESTION 1 Two glasses with equal quantities of water are at the same temperature. if the temperature of one is ralsed by 10 C and that of the other is...

    not the firsf picture. only the second QUESTION 1 Two glasses with equal quantities of water are at the same temperature. if the temperature of one is ralsed by 10 C and that of the other is raised by 10K, which one will be hotter? O The temperature of the first glass is more than the second, as each degree on the Celsius scale equals 1.8 degrees on the Kelvin scale. - The temperature of first glass is more than...

  • H1- COOLING TOWER [10 p] 1. What is the wet bulb temperature? How can you measure...

    H1- COOLING TOWER [10 p] 1. What is the wet bulb temperature? How can you measure it? Is the wet-bulb temperature greater than dry-bulb temperature? Why? [10 p] 2. A cooling tower is to be designed to cool 8 kg/s of water from 37°C to 29 °C. Entering air is 25 °C and at 30 % relative humidity. Leaving air is 22 °C and at 90% relative humidity. a) Calculate the air flow rate, G. b) Determine the possible lowest...

  • Ball bearings are hardened through a process of heating and then rapid cooling. The temperature of...

    Ball bearings are hardened through a process of heating and then rapid cooling. The temperature of the ball during this process can be estimated using the equation: T(t) = (ti-to)*e^(-t/T)+to where ti = initial ball temp = 800 degrees celcius to = initial oil temp = 40 degrees celcius    t = time = 0-180 seconds at 1 second intervals    T = time contraint Create a graph in matlab showing ball temperature versus time. the graph should have 3...

  • NAME: LAB QUIZ FOOD SAFETY NUTRITION SCI106 1. One way to safely thaw frozen poultry is a. at room temperature b. i...

    NAME: LAB QUIZ FOOD SAFETY NUTRITION SCI106 1. One way to safely thaw frozen poultry is a. at room temperature b. in cold water c. with a book of matches d. all of the above 2. To safely prepare leftovers a. reheat them to 130 degrees Fahrenheit b. reheat them to 165 degrees Fahrenheit c. reheat them in the microwave for one minute d. do not boil them 3. When grilling meat outdoors, you can avoid cross contamination by a....

  • If a potato core is allowed to dehydrate by sitting in open air, would the water potential of the potato cells decrease or increase

    If a potato core is allowed to dehydrate by sitting in open air, would the water potential of the potato cells decrease or increase? i think it decreases but i'm not sure. and if a plant cell has a lower water potential than its surroundings and if pressure=0, is the cell hypertonic(in terms of solute concentration) or hypotonic to its environment? will the cell gain or lose water? any ideas...?http://en.wikipedia.org/wiki/Water_potentialanalysis queswhat is water potential?Osmosis Lab /27819 Name: ________________________________ Date: ___________...

  • D. Addition of sulfuric acid to a flask of water is observed to increase the temperature...

    D. Addition of sulfuric acid to a flask of water is observed to increase the temperature of the flask. The creation of the mixture can be thought of as breaking interactions between water molecules (i.e., water - water interactions), breaking interactions between sulfuric acid molecules (i.e., sulfuric acid - sulfuric acid interactions) and forming new interactions between water and sulfuric acid (i.e., water - sulfuric acid interactions). Which of the following is true? Circle and explain your answer to receive...

  • Design the cooling system used to manufacture the leg of a table, shown in Fig.2. You...

    Design the cooling system used to manufacture the leg of a table, shown in Fig.2. You will have to determine the required diameter D so that the leg can withstand 100 kg of axial loading. Once the diameter has been determined, you will need to determine the Revolutions per Minute (RPMs) of the fan needed to cool down the leg to 90-C in less than 2 minutes before it starts deforming after being 3D printed. Consider the leg of the...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT